X^2-35x+68=0

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Solution for X^2-35x+68=0 equation: 



X^2-35X+68=0

a = 1; b = -35; c = +68;
Δ = b2-4ac
Δ = -352-4·1·68
Δ = 953
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{953}}{2*1}=\frac{35-\sqrt{953}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{953}}{2*1}=\frac{35+\sqrt{953}}{2}
$

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